In: Science

Submitted By mmgathee

Words 1486

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Words 1486

Pages 6

Name

Institution

Question one

Volume of figure one

Volume = area * length

Length = 7500M

Area = area of the outer big rectangle minus the area of the curve and the smaller inner rectangle * Area of the bigger rectangle = height * width

=9.6*8

=76.8 M2 * Area under the curve

We use the equation y=aX2 and solve for a with x and y coordinates as (3.6, 4.2), as this are the coordinates on the peak of the curve. a=0.3240740741 Our equation is: y= 0.3240740741x2 * Area under the curve =07.20.3240740741X2

=0.3240740741X33

= 40.32M2

Area of the inner rectangle= height * width

= 7.2 * 2

=14.4 m2

Total area =76.8-14.4-40.32

=22.08M2

VOLUME = 7500*22.08

=165,600M3

Volume of figure two.

The volume is found by multiplying the total area by height .

Height = 7500 M

Area is obtained by subtracting the area of the semicircle and inner rectangle from outer rectangle

Area of outer rectangle= width * height

=12*12.7

=152.4 M2

Area of the semicircle = R2

= * 3.652

=41.853868 M2

Area of the inner rectangle = height * width

= 5*7.3

=36.5 M2

Total area = 152.4- 41.85868-36.5

=74.046132 M2

Volume= 74.046132 M2 * 7500 M

=555,345.99 M3

Volume of figure three.

This is found by multiplying the height by the total area

Total area

Area of the outer rectangle minus the areas of the two 110 degrees circles .

Area of the rectangle = height * width

= 11 * 6

= 66 metres squared

Area of the circular parts =

110360 * 2 * 2.12* * 2= 16.9331844

Total area = 66- 16.9331844

=49.066815 M2

Volume = 49.066815* 7500

= 368,001.117 M3

B) * Figure one

The cost of constructing tunnel one will be the cost of concrete per cubic meter multiplied by the volume of of the tunnel.

= 120* 165,600

= £19,872,000 * Figure two

Cost = 555,345.99 *120

= £66,641,518.80 * Figure three

Cost =…...

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